
1) Initial velocity component :
> On the x axis ( horizontal ) => Vox = Vo cos a
> On the y axis (vertical) => Voy = Vo sin a
2) The vertical and horizontal motion of the body is the uniformly
> rectingular motion => Vx = Vox and x = Vox
> accelerated motion => Vy = Voy - gt and y = Voy.t - 1/2 gt2
3) When the ball reaches its highest point, the vertical component of the ball velocity is equal to zero or Vy= O, and the highest point it applier Vy = Voy sin a - gt = O will ressult:
> The time needed to reach the highest point: tp = Vo sin a : g
4) Subtitution of equation tp = Vo sin a : g with Vy = Voy - gt will result :
> Maximum height, that is ymaks = Vo2 sin2 a : 2g
5) With various elevation angles, it will obtain varied maximum heights also. The greatest maximum is obtained at the elevation angle a = 90 degrees
> The maximum horizontal distance is xmaks = Vo2 sin2 a : g
For example Click at here
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